Question 857628
Solve the following equation in the interval 0 < theta < 2pi. Give your final answers in radians correct to 3 sf

5*sin^2(theta)-3 =2sin(theta)+4cos^2(theta)
{{{5sin^2(x)-3=2sin(x)+4cos^2(x)}}}
{{{5sin^2(x)-3=2sin(x)+4(1-sin^2(x))}}}
{{{5sin^2(x)-3=2sin(x)+4-4sin^2(x)}}}
{{{9sin^2(x)-2sin(x)-7}}}
(9sinx+7)(sinx-1)=0
..
9sinx+7=0
sinx=-7/9
x&#8776;0.891
or
sinx-1=0
sinx=1
x=&#960;/2