Question 857269
{{{f(0)=-5}}}
{{{f(1)=1+5-5=1}}}
So somewhere between {{{x=0}}} and {{{x=1}}}, the function crosses the x-axis (has a zero).
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{{{graph(300,300,-2,5,-2,5,x^3+5x-5)}}}
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{{{f(0.8)=-0.488}}}
{{{f(0.9)=0.229}}}
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{{{f(0.85)=-0.136}}}
{{{f(0.87)=0.0085}}}
So split the difference.
{{{x=0.86}}}