Question 857313
 n is the sample size 
p is the population proportion 
p-hat is the sample proportion 
Use the Central Limit Theorem to find the Proportion probability. 
n = 101, p = 0.86, P (p-hat < 0.80) 
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z(0.80) = (0.80-0.86)/sqrt[0.86*0.14/101] = -1.7378
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P(p-hat < 0.8) = P(z < -1.7378) = normalcof(-100,-1.7378) = 0.0411
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Cheers,
Stan H.
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