Question 857266
4/x+1 and a width of 3/x-2


4/(x+1) and a width of 3/(x-2)

Perimeter = 2(l+h)

={{{2(4/(x+1)+ 3/(x-2))}}}


={{{2(4(x-2)+3(x+1))/((x+1)(x-2))}}}


{{{(2(4x-8+3x+3))/((x+1)(x-2))}}}


{{{2(7x-5)/((x+1)(x-2))}}}