Question 856963
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Hi,
p = .9,  n = 4
P(all four)= (.9)^4 = .6561
P(none) = (.1)^4 = .00009
Using TI
P(at least three) = binompdf(4, .9, 3) + binompdf(4, .9, 4)= .9477
P(x < 2) = (.1)^4 + binompdf(4, .9, 1) = .0037