Question 72218
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Find the equation of the line that goes through (1,-3) and is parallel to the line through y=-3x-5 

Remember:
   If the lines are parallel the slopes are the same
   Slope-intercept form of the equation y = mx + b, 
   m = slope and b = y - intercept

since the equation of the line we are looking for is parallel to y = -3x-5,
 Their slopes are the same. Therefore, the slope of the line we are looking
 for is -3.

Then the equation of the line passes through (1, -3),
we can now substitute the given m=-3, y=-3 and x = 1 to find b.

     -3 = -3(1) + b , 
     -3 = -3 + b
      0 = b

After getting the b or y-intercept, we can now find the equation of the line

 Use:   y = mx + b, m = -3 and b = 0
        y = -3x + 0
        y = -3

Graph
{{{graph (200, 200, -4, 6, -5, 7, -3x, -3x-5)}}}

Look at the red line, that's the equation of the line we are looking for
Notice that it passes (1,-3) and parallel to the other line with equation
equal to y = -3x-5.

I hope you understand the topic now. 

It's me
Rachel

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