Question 856789
a boat averages 20 mph in still water. It takes the boat the same amount of time to travel 3 miles with the currents as it does to travel 2 miles against the current. What is the currents rate?
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let c=rate of current
20+c=rate of boat with current
20-c=rate of boat against current
travel time=distance/rate (equal in both directions)
..
3/(20+c)=2/(20-c)
60-3c=40+2c
5c=20
c=4
rate of current=4 mph