Question 856560
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Hi,
  p = 1/3 , n =  10
P(x=5) = binompdf(n, p, x-value)= binompdf(10, 1/3, 5) = .1365

0r Using {{{P (x)= highlight_green(nCx)(p^x)(q)^(n-x) }}} 
{{{P (5)= highlight_green(10C5)(1/3)^5(2/3)^3 }}} 
{{{P (5)= highlight_green(252)(1/3)^5(2/3)^3 }}}