Question 855967
{{{SA=2*pi*R^2+2*pi*R*H}}}
but
{{{H=D=2R}}}
so then
{{{SA=2*pi*R^2+2*pi*R*(2R)}}}
{{{SA=2*pi*R^2+4*pi*R^2}}}
{{{SA=6*pi*R^2=200}}}
{{{R^2=200/(6*pi)}}}
{{{R^2=100/(3*pi)}}}
{{{R=sqrt(100/(3*pi))}}}