Question 856584
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Hi,
mean &#956; = 88 and standard deviation &#963; = 27
c)P(60 &#8804; x &#8804; 110)= normalcdf(60,110,88,27) = normalcdf(smaller, larger, µ, &#963;).
b)P(x &#8804; 110)= normalcdf(-999,110,88,27)  |-999 a place holder for smaller number
a) P(x &#8805; 60 = normalcdf(60,999,88,27)  |999 a place holder for larger number
d) P(x &#8805; 140 = normalcdf(140,999,88,27)  |999 a place holder for larger number