Question 856578
{{{log(sqrt(2),1/16)}}}
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If you recognize that 1/16 = {{{2^-4)}}}
Then {{{1/16 = (sqrt(2))^-8}}}
---> {{{log(sqrt(2),1/16) = -8}}}
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If not, then
{{{log(sqrt(2),1/16)}}}
= {{{log(1/16)/log(sqrt(2))}}}
= -8