Question 856514
what did You get for sample mean and use for standard deviation?
re Reply:
<pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
Yes, mean = 6.71
	x	x - 6.71	(x-6.71)^2
	6.1	-0.61	0.3721
	6	-0.71	0.5041
	6.3	-0.41	0.1681
	6.6	-0.11	0.0121
	7.7	0.99	     0.9801
	7.7	0.99	     0.9801
	7.8	1.09	     1.1881
	6.3	-0.41	0.1681
	6.4	-0.31	0.0961
	6.2	-0.51	0.2601
sum     	67.1		4.729
sum/10	6.71	   sum/9	0.525444444
		   sqrt(sum/9)	0.724875468
Sample SD = .725
a)  t = {{{(6.71-7.00)/(.725/sqrt(10)) = (-.29)/(.229) =highlight( -1.2664)}}}
ii) p-value =  NORMSDIST(-1.2664) = {{{ highlight_green(.1027)}}} .1027>.05  Sample does NOT show mean is <7