Question 856492
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Hi,
p(left-handed) = .08, p (right-handed) = 0.92,   n = 20
i)probability that right handed  {{{.92}}}
ii)probability that at most 2 are left handed: P(x &#8804; 2)= binomcdf(20,.08,2)
iii) mean and standard deviation for the number of left handed student
    mean = .08*20 = 1.6 , SD = sqrt(1.6*.92) = 1.233
round off as directed.