Question 855247
Graph the relation defined by the equation x^2+(y-3)^2 = 16 . Express the domain and the range of this relation in set-builder notation.
x^2+(y-3)^2 = 16
This is an equation of a circle with center at (0,3) and radius=4
domain: {x|[-4,4]}
range: {y|[-1,7]}
see graph below:
y=(16-x^2)^.5+3
{{{ graph( 300, 300, -10, 10, -10, 10, (16-x^2)^.5+3,-(16-x^2)^.5+3) }}}