Question 856404
Solve for x and y by elimination or substitution

{{{(x-2)/3 + (y+1)/5 =2}}}

multiply equation by 15
5(x-2)+3(y+1) = 30
5x-10+3y+3=30
5x+3y=37................................(1)

{{{(x+2)/7 - (y+5)/3 =-2}}}

multiply equation by 21  (7*3)

3(x+2)-7(y+5)=-42

3x+6-7y-35=-42
3x-7y=-13..................................(2)

5	x	+	3	y	=	37	.............1	
Total value								
3	x		-7	y	=	-13	.............2	
Eliminate	y							
multiply (1)by		7						
Multiply (2) by		3						
35	x		21	y	=	259		
9	x		-21	y	=	-39		
Add the two equations								
44	x				=	220		
/	44							
x	=	5						
plug value of			x	in (1)				
5	x	+	3	y	=	37		
25		+	3	y	=	37		
			3	y	=	37		-25
			3	y	=	12		
				y	=	4		
(5,4)