Question 856275
find the equation of the line that is perpendicular to the line x-3y-7=0 and passes through the point (9,-3)in standard form and general form
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Given Line DATA:
x - 3y - 7 = 0
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3y = x-7
y = (1/3)x -(7/3)
slope = 1/3
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New Line DATA:
Form:: y = mx + b
slope = -3
passes thru 9,-3
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-3 = -3*9 + b
b = 24
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New Equation:
y = -3x + 24
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Cheers,
Stan H.
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