Question 856275
find the equation of the line that is perpendicular to the line x-3y-7=0 and passes through the point (9,-3)in standard form and general form
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Standard form of equation for a line: y=mx+b, m=slope, b=y-intercept
Slope of given line=-3
Slope of line perpendicular to given line=negative reciprocal of slope of given line=-(1/-3)=1/3
Equation of perpendicular line:
y=x/3+b
solve for b using coordinates of given points line passes thru.
-3=9/3+b
b=-6
Equation: 
Standard form: y=x/3-6
or
General form: x-3y=18