Question 850717
<pre>
7 + 12 + 17 + 22 + 27 + 32

We find the nth term of the arithmetic sequence 7,12,17,22,27,32

{{{a[n]=a[1]+(n-1)d}}}

In the above series {{{a[1]=7}}} and d=12-7=17-12=22-17=27-22=32-27=5

{{{a[n]=a[1]+(n-1)d}}}
 
{{{a[n]=7+(n-1)(5)}}}

{{{a[n]=7+5(n-1)}}}

{{{a[n]=7+5n-5)}}}

{{{a[n]=2+5n}}}

{{{sum((2+5n),n=1,6)}}}

Edwin</pre>