Question 856038
Let one of the integer be x then, another number = 3x-10 
x^2 + (3x - 10)^2 = 100
x^2 + 9x^2 +100 - 60x = 100
10x^2 -60x = 0
10x^2 = 60 x
10 x = 60
x = 6

the other number is 3*6-10 => 8
The two integers are 6, 8