Question 855999
Solve for all real values of x in radians. {{{2cos^2(x)-5cos(x)+2=0}}}
(2cos(x)) - 1)*(cos(2x) - 2) = 0
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cos(x) = 1/2
x = pi/3 + 2n*pi, n = 0,1,2,3...
x = 5pi/3 + 2n*pi, n = 0,1,2,3...
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cos(x) = 1
x = 0 + n*pi, n = 0,1,2,3...