Question 72133
{{{5/(6-2i)}}}
{{{(5/(6-2i))((6+2i)/(6+2i))}}}Multiply both top and bottom by the complex conjugate of 6-2i
{{{(5*(6+2i))/(36+12i-12i-4(-1))}}}FOIL the denominator (remember {{{i^2=-1}}})
{{{(5*(6+2i))/(36+cross(12i-12i)-4(-1))}}}The i terms cancel in the denominator
{{{(5*(6+2i))/(40))}}}Distribute the 5 among the parenthesis
{{{(30+10i)/(40))}}}
{{{30/40+(10/40)i}}}
{{{3/4+(1/4)i}}}Here's the answer in a+bi form where a=3/4 and b=1/4