Question 855960
television has a width: height ratio of 9:3.
 If the television is advertised as having a 36 inch screen (remember the screen is measured as the diagonal), what is the actual height and width of the television?
The ratio can be reduced to 3:1
then
3x = the length
and
1x = the width
Pythag
x^2 + (3x)^2 = 36^2
x^2 + 9x^2 = 1296
10x^2 = 1296
x^2 = 1296/10
x^2 = 129.6
x = {{{sqrt(129.6)}}}
x = 11.3842" is the width
and
3(11.342) = 34.1526" is the length
:
What is the surface area of the screen?
34.1526 * 11.3842 = 388.80 sq/in