Question 855693
If (2, 1) and (1, 0) lie on the graph of x÷a + y÷b=1, then the values of a and b are
:
{{{x/a + y/b}}} = 1
:
x=2, y=1
{{{2/a + 1/b}}} = 1
:
x=1, y=0
{{{1/a + 0/b}}} = 1
{{{1/a}}} = 1
a = 1
replace a with 1 in the 1st equation
{{{2/1 + 1/b}}} = 1
2 + {{{1/b}}} = 1
{{{1/b}}} = 1 - 2
{{{1/b}}} = -1
b = -1
:
:
Check solutions in both statements