Question 855760
Simplify the following: 
3^-2 (x-1)^4 (xy^2)^3 z^5 / (9x^6)^1/2 y^4 (x-1)^-2 z^-1" 
the / is obviously "divided by".. 

My answer is written this way:
3^-2 (x-1)^4 (xy^2)^3 z^5 / (9x^6)^1/2 y^4 (x-1)^-2 z^-1 

= 1/9 (x-1)^4 x^3 y^6 z^5 / 3x^3 y^4 (x-1)^-2 z^-1 

= 1/9*3 (x-1)^4 (x-1)^2 x^3 x^-3 y^6 y^-4 z^5 z^1 -------------- Use * for multiply

= 1/3 (x-1)^6 x^0 y^2 z^6  ---------------- the 9*3 is in the DEN --> 1/27

= (x-1)^6 y^2 z^6 / 3
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Close
= {{{(x-1)^6*y^2*z^6 /27}}}