Question 855763
(a) 7 - 5x < -3 or 2x - 1 &#8804; x - 2
7 - 5x < -3
-5x < -10
when multiplying or dividing by a negative reverse the < or > 
x > 10
2x - 1 &#8804; x - 2
x &#8804; -1
so x is &#8804; -1 or > 10
there are two intervals to mark on the number line
(negative infinity, -1]  this is closed on the right because -1 is included
(10, infinity)
(b) 2 - 3x < 8 and 4x - 2 &#8804; 3x + 1
2 - 3x < 8
-3x < 6
x > -6
4x - 2 &#8804; 3x + 1
x &#8804; 3
so x > -6 and &#8804; 3
we have one interval which is closed on the right
(-6, 3]