Question 855572
Find the probability that a randomly selected person will have an IQ score above 102. mean of 103 and a standard deviation of 16
z(102) = (102-103)/16 = -1/16
P(x > 102) = P(z > -1/16) = normalcdf(-1/16,100) = 0.4751
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The weights of ripe watermelons grown at Mr. Smith's farm are normally distributed with a standard deviation of 2.7 lb. Find the mean weight of Mr. Smith's ripe watermelons if only 8% weigh less than 12 lb. (Give your answer correct to one decimal place.)
Find the z-score with a left tail of 12%:: invNorm(0.12) = -1.1750
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Use x = z*s+u to find "u":
12 = -1.1750*2.7 + u
u = 15.17 lbs
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Cheers,
Stan H.
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