Question 855513
From the two given equations,
{{{(2^4)^x *(2^2)^y=2^6}}}
{{{2^(4x+4y)=2^6}}}
{{{highlight(4x+4y=6)}}}
and
{{{(5^2)^x/(5^3)^y=5^(1/2)}}}
{{{5^(2x-3y)=5^(1/2)}}}
{{{highlight(2x-3y=1/2)}}}
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Your system to solve is then this:
{{{4x+4y=6}}} and {{{2x-3y=1/2}}}
Simplification gives you:
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{{{highlight(2x+2y=3)}}} and {{{highlight(4x-6y=1)}}}
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You should now find this system easier to handle.