Question 72076
<pre>
             n^2 - 8n + 12
          __________________   , Remember that n^3 - 12n^2 + 36n&#8800;0
           n^3 - 12n^2 + 36n

            Factor both numerator and denominator

            (n - 6)(n - 2)
           _______________ , n &#8800; 6, so 6 is the excluded value
            (n - 6)(n - 6)

           Divide the common factor/s
           {{{cross(n - 6)(n - 2)}}}
           ______________
           {{{cross(n - 6)(n - 6)}}}



           (n - 2)
           _______    -------->> answer
           (n - 6)