Question 855384
Find the number of solutions of 
sin theta + 2 cos theta =0 
over the interval [-pi,pi/2].
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Divide thru by cos(t) to get:
tan(t) + 2 = 0
tan(t) = -2
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t = arctan(-2) = -1.1070 in QIV
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t = -1.1070+pi = 2.0344 in QII
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Cheers,
Stan H.
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