Question 855313
The polynomial is in quadratic form.  You can replace like, {{{u=x^2}}}.  The constant terms in each binomial factor will need to give product of 11 and sum of -12.  The obvious and correct choice will be -1 and -11.


{{{(x^2-1)(x^2-11)=0}}}
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The solutions will be Real Numbers:
EITHER {{{x^2-1=0}}}
{{{x^2=1}}}
{{{x=1}}} or {{{x=-1}}}
OR
{{{x^2-11=0}}}
{{{x^2=11}}}
{{{x=sqrt(11)}}} or {{{x=-sqrt(11)}}}


SUMMARY:  possible solutions for x are -1, 1, -sqrt(11), sqrt(11)