Question 855270
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Hi,
i) P(at least one six) = 1 - P(no six) = 1 - (5/6)^4 = = 1-binomcdf(4,1/6,0)= .5178 
ii)  P(at least one six | no one) = 1 -(4/5)^4=  1-binomcdf(4,1/5,0)= .5904
iii)  P(No 1 | at least one six) = .5904