Question 855240
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Hi,
x^4-4x^2-32 = (x^2 + 4)(x^2 - 8) 
2x^4+11x^2+12 = (2x^2 + 3)(x^2 + 4)
 
x^4-4x^2-32/2x^4+11x^2+12 = (x^2-8) / (2x^2 + 3)