<PRE><B>Question 72059</B>
The sum of n and three subtracted from twelve times n is the same as negative eleven plus the product of 2 and the difference of n and five.
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EQUATION:
12n-(n+3)=-11+2(n-5)
12n-n-3 = -11+2n-10
11n-3 = 2n-21
9n = -18
n=-2

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Cheers,
Stan H.</PRE>