Question 855229
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Hi,
b. 10*.53 = 5.3  Expect 5
c. sqrt(.53*.47/10)
d. p = .53 ,  n = 10  P(x=6)= binompdf(10, .53, 6)= .2271
e. P( x < 6) =  binomcdf(10, .53, 5) = .5474
f.  P( x < 120) =  binomcdf(250, .53, 119) = .4987
recommend stattrek.com as a  reference