Question 72056
<pre><font size = 4><b>
                {{{(6x^2y^3+9x^2y^3)/(3x^2y^3)}}}

The two terms in the numerator are like terms,
so simply add them and get

                  {{{(15x^2y^3)/(3x^2y^2)}}}

Cancel the {{{3}}} into the {{{15}}} and then cancel
the {{{x^2}}}'s and the {{{y^2}}}'s and you end up 
with just the number

                     {{{5}}}

Edwin</pre>