Question 855178
(3,-1) and (2,3)

The mid point will be (3+2)/2 = (5/2)

(-1+3)/2 = 2/2 = 1

The co-ordinates of mid point are ( (5/2),1 )

If this lies on the line 8y - 2x - 3=0

It must satisfy the equation

Plug the co ordinates of the mid point

8*1 -2*(5/2)-3 =0

LHS = RHS
so the midpoint lies on the line