<PRE><B>Question 855192</B>
The length of a rectangle is 7 feet longer than it is wide. If each side is increased 7 feet, then the area is multiplied by 4. What was the size of the original rectangle?
Answer
Let  width of rectangle is x feet
length will be x+7 feet

area of rectangle =lenghxwidth
 area  of rectangle =x(x+7)
now as per given conditions  if 7 feet is increased  area willbe 4 times
new width =x+7
length =x+7+7=x+14
new area will be =(x+7)(x+14)
as  per given conditions 
(x+7)(x+14)=4x(x+7)
x^2+21x+98=4x^2+28x
0=4x^2+28x-x^2-21x-98
3X^2+7x-98=0
3x^2-14x+21x-98=0
x(3x-14)+7(3x-14)=0
x+7=0 or 3x-14=0
x=-7 0r x=14/3 feet 
neglecting negative 7  as diamension can not be negative 
width =14/3 feet 
and length=14/3+7=35/3 feet 
Answer
length will be =35/3 feet
width  will be =14/3 feet
verification
area=14/3x35/3
new area will be 
 =56/3x35/3=4(14/3x35/3)  verified as per condition  area 4 times of old area </PRE>