Question 855108
In fact you are correct.  Keep going with it.


How to put into base 2, and use the rendering tagging:   log(-x-3)-log(x-1)-log(x+3)= 1;


log(2,(-x-3))-log(2,(x-1))-log(2,(x+3))=1.
Put three left-curly braces at the left and three right-curly braces at the right, and this will make the algebra dot com message field <i>render</i> the expression or equation.


Left curly brace, {
Right curly brace, }.


{{{log(2,(-x-3))-log(2,(x-1))-log(2,(x+3))=1}}}