Question 855096
The trick is to express {{{ 2 }}} as a log
{{{ 2 = log( 100 ) }}}
{{{ 2*log( x ) + log( 4 ) = 2 }}}
{{{ 2*log( x ) + log( 4 ) = log( 100 ) }}}
{{{ log( x^2 ) + log(4) = log( 100 ) }}}
{{{ log( 4x^2 ) = log( 100 ) }}}
{{{ 4x^2 = 100 }}}
{{{ x^2 = 25 }}}
{{{ x = 5 }}}
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check:
{{{ 2*log( x ) + log( 4 ) = 2 }}}
{{{ 2*log( 5 ) + log( 4 ) = 2 }}}
{{{ 2*.69897 + .60206 = 2 }}}
{{{ 1.39794 + .60206 = 2 }}}
{{{ 2 = 2 }}}
Ok
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Also note that {{{ x = -5 }}} the other square root
doesn't work because {{{ log(( -5 )) }}} makes no sense.
You can't raise base 10 to an exponent and
get a negative result.