Question 854988
The equation of a line perpendicular to the given line but passing through the given point y=-2/3x+2 (9,-3)
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That line has a slope of -2/3
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Your line must have a slope of 3/2 because their product must be -1.
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Form of your equation: y = mx + b
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Solve for "b":
-3 = (3/2)(9) + b
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-6/2 = 27/2 + b
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b = -33/2
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Equation:
y = (3/2)x - (33/2)
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Cheers,
Stan H.
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