Question 854913
<pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
Log5 (y+ 1) - log5 8 = log5 (y- 3) - log5 6
Log5 (y+ 1) - log5 8 - log5 (y- 3) + log5 6 = 0
Log5 6(y+ 1)/8(y-3)= 0
   {{{6(y+ 1)/8(y-3)= 1}}}
    6y + 6 = 8y - 24
         30 = 2y
         15 = y