Question 854822
<pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
(1/a+3)-(a/a^2-9)=(2/3-a)
1/(a+3)- a/(a+3)(a-3)= -2/(a-3)  |Note Parenthesis used to show terms in denominator 
|Multiplying thru by (a+3)(a-3) so as all denominators = 1
 (a-3) - a + 2(a+3) = 0
      2a +3 = 0
       2a = -3
        a = -3/2