Question 854758
Let a - be one of the number
    b - be the second number

When given a question of this nature, you can look upon the two numbers as the factors in two polynomials that give you a quadratic when multiplied. That sounds complicated, but I mean this: 

{{{(x + a)(x + b) }}}

Use our friend Mr. Foil

{{{x^2 + (a + b)x + ab }}}

So they give you a product of "ab" and a sum of "a + b". You are looking for exactly that, two numbers that multiply to give a product you specify and add to give the sum you specify. 

If you substitute the sum, -1, and the product, -60, you get: 

{{{x^2+(-1)x+(-60)-0}}}
{{{x^2-x-60=0}}} Since it's not a perfect trinomial we use completing the square
{{{x^2-x+1/4=60+1/4}}} It's 1/4 because 3rd term = ((-1)/2)^2
{{{sqrt(x-1/2)^2=sqrt(60*1/4)}}}
{{{x-1/2=sqrt15}}}
{{{x=sqrt15+1/2}}}


Hope that helps!