Question 206555
Find the distance to the point, that's the radius. By the formula d= &#8730;(x2-x1)^2+ (y2-y1)^2  
&#8195;
d= &#8730;(3+5)^2+ (-1-1)^2  
d= &#8730;64+4 = &#8730;68 (or =r)
r^2=68

Then it's (x-h)^2 + (y-k)^2 = r^2 (h,k) is the center
(x-3)^2 + (y+1)^2 = 68