Question 854657
I have previously asked this question, question #853406, but didn't really get help.

Find all real solutions to the equation.

t^-3/2=64

The answer that I was given was 1/16, however, I don't know how they got this answer.  Can someone please help in showing or explaining the work on how to get to this conclusion?

Thank you in advance for the help.
<pre>
{{{t^(-3/2) = 64}}}
{{{t^((- 3/2)*(2/3)) = 64^(2/3)}}} 
{{{t^((-cross(3)/cross(2))*(cross(2)/cross(3))) = 64^(2/3)}}}
{{{t^-1 = 64^(2/3)}}}
{{{t^-1 = 4^2}}}
{{{t^-1 = 16}}}
{{{1/t^1 = 16}}}
{{{1/t = 16}}}
16t = 1 ------ Cross-multiplying
{{{highlight_green(t = 1/16)}}}

You can do the check!! 

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