Question 854657
Maybe you misunderstood the notation according to what you were given?  Try the equation as {{{highlight_green(t^(-3/2)=64)}}} and solve for t accordingly.   (If problems in rendering, the exponent is negative three halves).


Here is a few steps into solving. (unfortunately, the rendering is still bad).
{{{1/(t^(3/2))=64}}}  because of the given negative exponent;
{{{t^(3/2)=1/64=1/(2^3*2^3)}}}
{{{t^(3/2)=1/(2^6)}}}
...Can you see what steps can be done next?  Can you finish and have {{{t=1/16}}}?