Question 854461
<pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
log -5x - log 8 = 1
log -5x/8  = 1
  10^1 = -5x/8
    10 = -5x/8
    -80/5 = -16 = x 
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]