Question 854427
Use a substitution, {{{u=tan(x)}}}
{{{3u^2+4u-4=0}}}
{{{(3u-2)(u+2)=0}}}
Two solutions:
{{{3u-2=0}}}
{{{3u=2}}}
{{{u=2/3}}}
{{{tan(x)=2/3}}}
{{{x=atan(2/3)}}}
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{{{u+2=0}}}
{{{u=-2}}}
{{{tan(x)=-2}}}
{{{x=atan(-2)}}}