Question 854420
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Hi,
f(x)=3x^3-43x^2+161x-49    |Yes x = 7 is a root
Using synthetic Division to find the other two
7	3	-43	161	-49
		21	-154	49
	3	-22	7	 0
    3x^2 - 22 + 7
   ( 3x - 1)(x - 7) = 0 , x = 7 , x = 1/3
f(x)=3x^3-43x^2+161x-49 = (x-7)(x-7)(x - 1/3)

f(x)=2x^3-4x^2-34x+68  x = 2 is a root
Using synthetic Division to find the other two
2	2	-4	-34	68
		4	0	-68
	2	0	-34	0
        2x^2 = 34 = 0
         x = ± &#8730;17
f(x)=2x^3-4x^2-34x+68 = (x-2)(x + &#8730;17)( x -&#8730;17)