Question 71851
A bacteria culture started with a count of 720 at 8:00 am, and after t hours is
 expected to grow to f(t)=720(3/2)^t. Estimate the number of bacteria in the 
culture at 11:00 am the same day.
:
That would be after 3 hrs, can be done directly on a calc, however if they want you to use logs:
:
y = f(t) 
y = 720(3/2)^3
ln(y) = ln(720) + ln(3/2)^3
ln(y) = 6.57925 + 3*ln(.405465); log equiv of exponents
ln(y) = 6.57925 + 1.2164
ln(y) = 7.795645
y = e^x of 7.795645 = 2429.99 ~ 2430
:
Check on a good calc: enter: 720*(1.5^3)